makepkg: remove distcc/makeflags option interaction

Way back in c94bfbaba when refactoring makepkg options handling, I added
these lines to unset MAKEFLAGS if '!distcc' was set in a PKGBUILD (not
taking into account makepkg.conf settings). This was an attempt to say
"if it is broken in distcc, it is probably broken even more". However,
this is silly as one should be using '!makeflags' as well. Remove the
linkage.

Signed-off-by: Dan McGee <dan@archlinux.org>

1 files changed, 0 insertions, 3 deletions

diff --git a/scripts/makepkg.sh.in b/scripts/makepkg.sh.in
index 239bb642..cd94ac98 100644
--- a/scripts/makepkg.sh.in
+++ b/scripts/makepkg.sh.in
@@ -822,9 +822,6 @@ run_build() {
 	if [[ $(check_buildenv distcc) = "y" && $(check_option distcc) != "n" ]]; then
 		[[ -d /usr/lib/distcc/bin ]] && export PATH="/usr/lib/distcc/bin:$PATH"
 		export DISTCC_HOSTS
-	elif [[ $(check_option distcc) = "n" ]]; then
-		# if it is not wanted, clear the makeflags too
-		MAKEFLAGS=""
 	fi
 
 	# use ccache if it is requested (check buildenv and PKGBUILD opts)